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2^1/4x+1/2x=44
We move all terms to the left:
2^1/4x+1/2x-(44)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
4x^2/8x^2+4x/8x^2-44=0
We multiply all the terms by the denominator
4x^2+4x-44*8x^2=0
Wy multiply elements
4x^2-352x^2+4x=0
We add all the numbers together, and all the variables
-348x^2+4x=0
a = -348; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-348)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-348}=\frac{-8}{-696} =1/87 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-348}=\frac{0}{-696} =0 $
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